Circus Casino Online

Circus Casino Online Average ratng: 9,6/10 5425 reviews
1 vote (16.66%)
No votes (0%)
3 votes (50%)
No votes (0%)
No votes (0%)
No votes (0%)
No votes (0%)
No votes (0%)
1 vote (16.66%)
1 vote (16.66%)
  1. Circus Fruits is a 5-reel, 243-line online slot game with bonus round, bonus spins, instant play, autoplay, video slots, multiplier, wild symbol, scatter symbol, cascading reels, mobile gaming, fruit/vegetables, circus and entertainment themes you can play at 2 online casinos.
  2. Circus Casino is one of several online casinos run by the Genting Group, the UK's largest land-based casino operator. The casino uses games from the world's largest software provider, Playtech, ensuring that players will have a vast array of modern games to select from.

Circus บ่อนคาสิโน ชื่อเสียงโด่งดัง ที่สุดใน Las Vegas ประเทศ สหรัฐอเมริกา (United State Of America) ได้จดทะเบียนในรูปแบบ บริษัทให้บริการ.

6 members have voted

Circus Club Online Casino

Cirrus casino online
ksdjdj

1/(2n-2)?


Especially when n = 1, ; )
edit:
sorry, I don't know the answer, but this thread looked interesting
TigerWu
Anywhere to the left or right of the middle.
If he sets up in the middle, that will leave too many people to the left or right of him for the other vendors to nab.
If he sets up off-center, because the people are distributed evenly, he is guaranteed to cut out customers for one of the vendors since they won't be able to set up their stands evenly.
1 vote (16.66%)
No votes (0%)
3 votes (50%)
No votes (0%)
No votes (0%)
No votes (0%)
No votes (0%)
No votes (0%)
1 vote (16.66%)
1 vote (16.66%)

6 members have voted

unJon

This could easily be wrong, but here is where I'm at with the four-vendor case:
Vendor 1 picks a spot a smidge to the left of 0.1
Vendor 2 picks a spot a smidge to the right of 0.9
Vendor 3 will be indifferent between 0.4 and 0.6. Let's just say he picks 0.4
Vendor 4 will pick 0.65.
This would give space as follows:
Vendor 1 0.25
Vendor 2 0.275
Vendor 3 0.25
Vendor 4 0.225
However, Vendor 3 could pick the spot closer to vendor 2. It would average out to:
Vendor 1 0.2375
Vendor 2 0.2750
Vendor 3 0.2500
Vendor 4 0.2375
Thoughts?

Let’s try a simplifying assumption. A and B will want to be at the lowest and highest spots because tending too far away from an end leave them open to C and D grabbing that territory that is unshared to the beach ends. A and B will pick spots such that the distance to the island end is half the distance that C and D could claim in the middle (since middle beach territory only runs to the midpoint to the next vendor).
If that holds let’s run a test where A goes to 1/5 mile mark. If 3 vendors means A goes to 1/4, then maybe it’s as simple as A going to 1/(1+n)? And B responds by going to 4/5 mile marker.
C will want to make D indifferent about going to the left or right of him. That means C will go to 1/2 and D will land a smidge to the right or left of C. This is generally true of a two vendor problem, which is exactly what the four vendor problem reduces to (since A and B simply “shrink” the useable end points of the beach). C and D capture territory of (1/2 - 1/5) / 2 = 3/20.
Since 3/20 territory is worse than D could have done by cutting A or B off from the end (capturing 1/5 or 4/20), that means A and B are too far from the island edge.
The indifference equation then is A - 0 = (1/2 - A)/2. So A should equal 1/6.
So A goes to 1/6 (or a smidge less), B goes to 5/6 (or a smidge more), C goes a smidge to the left (or right) of 1/2 and D takes the middle.

Looks like my answer agrees with Charliepatrick’s.
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
charliepatrick

...C goes a smidge....

Last night I wasn't sure why C would go to the middle. In the two vendor case whereever C goes D goes next door. However in this case D is indifferent where he goes on the segment, except it will be the larger segment remaining, as the other end is shared with A or B. In fact D gets half the segment between C and either A or B.
Thus if C leaves a larger segment on one side then D gets a larger slice than C going in the middle. It didn't seem obvious this would be to the detriment of C.
For argument's sake (since we're looking at C) look at various points where C is nearer to A. C will share that segment so has a AC/2 slice.
D picks a point randomly between C and B, so on average CD = CB/2. Thus C's slice is CB/4. The total of the two slices is (AC/4+AC/4)+CB/4=AC/4+AB/4. Thus C should maximise AC and pick the middle.
unJonOnline
Thanks for this post from:
Last night I wasn't sure why C would go to the middle. In the two vendor case whereever C goes D goes next door. However in this case D is indifferent where he goes on the segment, except it will be the larger segment remaining, as the other end is shared with A or B. In fact D gets half the segment between C and either A or B.
Thus if C leaves a larger segment on one side then D gets a larger slice than C going in the middle. It didn't seem obvious this would be to the detriment of C.
For argument's sake (since we're looking at C) look at various points where C is nearer to A. C will share that segment so has a AC/2 slice.
D picks a point randomly between C and B, so on average CD = CB/2. Thus C's slice is CB/4. The total of the two slices is (AC/4+AC/4)+CB/4=AC/4+AB/4. Thus C should maximise AC and pick the middle.
That makes sense to me.
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
Circus casino online
Wizard
Administrator

Looks like my answer agrees with Charliepatrick’s.


I agree and stand corrected.
It's not whether you win or lose; it's whether or not you had a good bet.
Wizard
Administrator
How about the case of n pirates? Let's think of it in terms of units of space, as opposed to 1 mile.

The first two vendors to act will pick spots a smidge less than 1 unit from either edge.
Vendors 3 to n-2 will pick spots 2 minus a smidge units away from already established vendor
Vendor n-1 will pick a spot exactly between the closest vendors in the progressions from each end.
Vendor n will be indifferent between the spot exactly between n-1 and one of the vendors to his side, because he will get a full unit, as opposed to one unit minus a smidge.
At the end of the day:
Vendors 1 and 2 will get 1.5 units of space
Vendors 3 to n-4 will get 1 unit each
Vendors n-2 and n-3 will get 1 and 1.5 units each. Who gets how much will depend on n's action.
Vendor n-1 will get 1.5 units
Vendor n will get 1 unit.
p.s. Why doesn't my spell checker like 'smidge?'
p.p.s Do I put the question mark inside or outside the right quote?
Circus Casino Online

Circus Casino Online Casino

It's not whether you win or lose; it's whether or not you had a good bet.
unJon

How about the case of n pirates. Let's think of it in terms of units of space, as opposed to 1 mile.


The first two vendors to act will pick spots a smidge less than 1 unit from either edge.
Vendors 3 to n-2 will pick spots 2 minus a smidge units away from already established vendor
Vendor n-1 will pick a spot exactly between the closest vendors in the progressions from each end.
Vendor n will be indifferent between the spot exactly between n-1 and one of the vendors to his side, because he will get a full unit, as opposed to one unit minus a smidge.
At the end of the day:
Vendors 1 and 2 will get 1.5 units of space
Vendors 3 to n-4 will get 1 unit each
Vendors n-2 and n-3 will get 1 and 1.5 units each. Who gets how much will depend on n's action.
Vendor n-1 will get 1.5 units
Vendor n will get 1 unit.
p.s. Why doesn't my spell checker like 'smidge?'
p.p.s Do I put the question mark inside or outside the right quote?

1) Pirates on the brain! :-)
2) I’d put the ? Outside the quotes there.
The race is not always to the swift, nor the battle to the strong; but that is the way to bet.
Ayecarumba

How about the case of n pirates? Let's think of it in terms of units of space, as opposed to 1 mile.


The first two vendors to act will pick spots a smidge less than 1 unit from either edge.
Vendors 3 to n-2 will pick spots 2 minus a smidge units away from already established vendor
Vendor n-1 will pick a spot exactly between the closest vendors in the progressions from each end.
Vendor n will be indifferent between the spot exactly between n-1 and one of the vendors to his side, because he will get a full unit, as opposed to one unit minus a smidge.
At the end of the day:
Vendors 1 and 2 will get 1.5 units of space
Vendors 3 to n-4 will get 1 unit each
Vendors n-2 and n-3 will get 1 and 1.5 units each. Who gets how much will depend on n's action.
Vendor n-1 will get 1.5 units
Vendor n will get 1 unit.
p.s. Why doesn't my spell checker like 'smidge?'
p.p.s Do I put the question mark inside or outside the right quote?

Circus casino onlineWhat if none of the vendors knows n? Will vendor 1 set up in the middle of the strand?
Simplicity is the ultimate sophistication - Leonardo da Vinci

Circus Circus Online Casino

charliepatrick

What if none of the vendors knows n? Will vendor 1 set up in the middle of the strand?

I'd guess the correct logic is the first person goes in the middle and the rest just go in the middle of the largest gap left. Thus three people would be at 25% 50% and 75%, seven at 1/8 2/8... 7/8 etc.
Wizard
Administrator

What if none of the vendors knows n? Will vendor 1 set up in the middle of the strand?


They know what n is.
It's not whether you win or lose; it's whether or not you had a good bet.

Circus Circus Casino Tower Room

99kv99

Circus Circus Hotel Casino Theme Park

1/(2n-2)?